Administrace komentářů

Resp. toto je blizsie k rieseniu.

1. Upraveny reg. vyraz, aby vyzadovalo po #! znak / (root), na rozdiel od predchadzajuceho prikladu.

2. Riesi symlinky ako napr. /bin/sh je v debian unstable symlink na /bin/dash

3. Riesi pripad, ak je pouzity #! /usr/bin/env interpreter

4. Riesi medzery, ktore potencialne mozu byt za znakmi #!

#!/bin/bash

SearchPath()
{
declare dir
declare -r oldifs="$IFS"
IFS=':'

for dir in $PATH
do
        [ -x "$dir"/"$1" ] && interpreter="$dir"/"$1" && IFS="$oldifs" && return 0
done
IFS="$oldifs"
return 1
}

FindInterpreter()
{
declare interpreter script_path
script_path="$1"
# this way it reads the very first line of chosen script only
read first_line <"$script_path"

# the very first with the very first two characters #! , folowing or not by space
# and a path to an interpreter.Allowed characters are letters, numbers, underscore,
# dot and hyphen.
if [[ "$first_line" =~ ^#![[:space:]]*(/[/,_,-,.,a-Z,0-9]*)[[:space:]]*([_,-,.,a-Z,0-9]*) ]]
then
        if [ "${BASH_REMATCH[1]}" == '/usr/bin/env' ]
        then
                interpreter="${BASH_REMATCH[2]}"
                if SearchPath "$interpreter"
                then
                        echo -e "Skript: $script_path\nInterpreter: "$(readlink -f "$interpreter")""
                else
                        echo -e "Skript: $script_path\nInterpreter: $interpreter sa nenachadza v ziadnej z ciest v PATH.\nJe nainstalovany?"
                fi
        else
                interpreter="${BASH_REMATCH[1]}"
                echo -e "Skript: $script_path\nInterpreter: "$(readlink -f "$interpreter")""
        fi
else
        echo -e "Chybajuci shebang.\nSi si isty, ze $script_path je skript ?"
        return 1
fi
}

FindInterpreter "$1"

Nevravim, ze je to idealne riesenie a dokonca to moze mat aj chyby, ale aspon je vidiet, ze sa to da spravit aj cisto v bash-i a inych shell-och isto tiez. A dokonca nikto nevravil ani opak. :) Tak som sa aspon pobavil.