Portál AbcLinuxu, 8. května 2025 11:34
CREATE FUNCTION accounting.basefun( IN var_year character, IN var_month character) RETURNS TABLE( account character, debit11 double precision, credit11 double precision, debit double precision, credit double precision, debitxx double precision, creditxx double precision) AS $BODY$ ..... ......Nyní potřebuji ji použít jako zdroj dat v jiné funkci , tam jsem narazil na problém s identifikací sloupců.
CREATE FUNCTION extfun( IN var_year character, IN var_month character) RETURNS TABLE( account character, accountname character, debit11 double precision, credit11 double precision, debit double precision, credit double precision, debit1x double precision, credit1x double precision, debitxx double precision, creditxx double precision, debitact double precision, creditact double precision ) AS $BODY$ SELECT ledg.account, //error Zde nemohu přijít jak identifikovat sloupce ledg.debit11, ledg.credit11 ......... FROM (SELECT accounting.basechangeledger(var_year,var_month) ) AS ledg $BODY$Předem dík za nakopnutí správným směrem.
Řešení dotazu:
(SELECT * FROM accounting.basechangeledger(var_year,var_month) ) AS ledgTvůj zápis sešrotuje sloupce do pole a vrací to jako jeden sloupec, jestli se nepletu.
CREATE FUNCTION accounting.test( IN var_year character, IN var_month character) RETURNS TABLE( account character, debit11 double precision, credit11 double precision, debit double precision, credit double precision, debitxx double precision, creditxx double precision ) AS $BODY$ SELECT * FROM (SELECT accounting.basefunc(var_year,var_month) ) AS ledg $BODY$ LANGUAGE sql VOLATILE
SELECT accounting.basefunc(var_year,var_month)
vola funkciu vracajucu "sadu" (set returning function). Ak ju zavolas priamo v SELECT klauzule, tak musi vratit cely viacstlpcovy riadok v jedinom stlpci typu ROW(*). Predrecnik to sice chybne oznacil ako pole, ale trafil pricinu problemu. Je to to iste, ako keby si zavolal
SELECT ROW(e.*) FROM accounting.basefunc(var_year,var_month);
Ak chces pracovat s jednotlivymi stlpcami, musis to volat ako SELECT * FROM accounting.basefunc(var_year,var_month)
.
Tvoja funkcia by potom mohla vyzerat takto:
BODY$
SELECT
ledg.*,
ledg.debit11,
ledg.credit11
FROM
(SELECT *
FROM accounting.basechangeledger(var_year,var_month)
) AS ledg
$BODY$
co je ale to iste ako:
BODY$
SELECT
ledg.*,
ledg.debit11,
ledg.credit11
FROM accounting.basechangeledger(var_year,var_month) AS ledg
$BODY$
Tiskni
Sdílej:
ISSN 1214-1267, (c) 1999-2007 Stickfish s.r.o.