Portál AbcLinuxu, 9. května 2025 05:58
SELECT * FROM `nazev-databaze1.tabulka`
SELECT `nazev-databaze1.tabulka.*`, `nazev-databaze2.jinatabulka.*` FROM `nazev-databaze1.tabulka` INNER JOIN `nazev-databaze2.jinatabulka` ON `nazev-databaze1.tabulka.id` = `nazev-databaze2.jinatabulka.id` WHERE `nazev-databaze1.tabulka.public`=1
Řešení dotazu:
nazev-databaze1.tabulka
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SELECT * FROM `nazev-databaze1`.`tabulka`
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