Dotaz: python - rozdilne chovani pri volani z bash a primo

[1john2]

Dobry den,

mam zajimavy problem.

#!/bin/bash python -c "import crypt, getpass, pwd;clear=getpass.getpass(); print crypt.crypt(clear, '\$6\$SALTsalt\$');"

Spravne vytvori sha-512 hash hesla.

#!/usr/bin/python import crypt, getpass, pwd;

print "Zadejte heslo administratora:"

clear = getpass.getpass()

print crypt.crypt(clear, '\$6\$saltSLAT\$')

print clear

Sice vytvori hash ale jiny, pravdepodobne des.

Napada vas co musim nastavit aby se kod choval stejne?

Dekuji za kazdy napad

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Odpovědi

[chrono]

Chyba je v tej python variante:

#!/usr/bin/python
import crypt, getpass, pwd
print "Zadejte heslo administratora:"
clear = getpass.getpass()
print crypt.crypt(clear, '$6$SALTsalt$')
print clear

[chochi]

Presne - to co presne zavola bash oneliner se da zjistit, napr pomoci echo:

$ echo "import crypt, getpass, pwd;clear=getpass.getpass(); print crypt.crypt(clear, '\$6\$SALTsalt\$');"
import crypt, getpass, pwd;clear=getpass.getpass(); print crypt.crypt(clear, '$6$SALTsalt$');

[1john2]

diky za rychlou odpoved, takze kdyz volam primo python nemusim $ escapovat?

[chochi]

V Pythonu nema znak '$' specialni vyznam (narozdil od Bashe nebo napr Perlu), tudiz se nemusi escapovat. On se spis nesmi escapovat, viz dokumentace:

Unlike Standard C, all unrecognized escape sequences are left in the string unchanged, i.e., the backslash is left in the string. (This behavior is useful when debugging: if an escape sequence is mistyped, the resulting output is more easily recognized as broken.)

Tudiz '\$' je stejne jako '\\$'.